Emuva esikoleni. impande kwalokho

amakhompyutha electronic Namuhla yesimanje kubalwa impande skwele inombolo akuyona msebenzi onzima kangaka. Ngokwesibonelo, √2704 = 52, lona ukubala yimuphi wokubala. Ngenhlanhla, umshini wokubala akuyona kuphela ku-Windows, kodwa futhi avamile, ngisho linesizotha kakhulu, ifoni. Iqiniso uma ngokungazelelwe (okungenzeka ongaphakeme, ikhompyutha zazo, ngenhlanhla kuhlanganisa kwalokho izimpande), uzothola ngokwakho ngaphandle izimali ke, maye, kudingeke ukuba sincike ubuchopho bazo.

Ukuqeqesha ingqondo ongakaze afake. Ikakhulukazi kulabo abangekho kaningi isebenza nge izinombolo, nakakhulu ne izimpande. Kuhlanganisa nekususa umsuka - Amazing kuhle umqondo unesizungu. Futhi Ngizokukhombisa step by step kwalokho izimpande. Isengezo Izibonelo kungenzeka kanje.

I kwesibalo okumele lula:

√2 + 3√48-4 × √27 + √128

Lena inkulumo engenangqondo. Ukuze lula kubalulekile ukuletha zonke radicands efomini jikelele. Asazi step by step:

Inombolo yokuqala ayikwazi lula. Siphendukela kwethemu yesibili.

3√48 ukubola at multipliers 48: 48 = 2 × 24 noma 48 × 16 = 3. Impande square ka 24 akuyona inamba, isb umsalela wamaqhuzu. Njengoba kudingeka ukubaluleka ngqo, izimpande eseduze ayifanele. Impande eyisikwele 16 ezine, ukwenza kube ngaphansi uphawu impande. We ukuthola 4 × 3 × √3 = 12 × √3

Amazwi alandelayo kithi alivumi, okungukuthi, silotshiwe lokususa -4 × √ (27.) Sabalalisa 27 multipliers. We ukuthola 27 × 3 = 9. Asisebenzisi multipliers wamaqhuzu ngenxa amafraktjhini ukubala impande skwele eyinkimbinkimbi. 9 ukuthatha lisuke ngaphansi ipuleti, isb Thina ukubala impande square. Thina ukuthola isisho ezilandelayo: -4 × 3 × √3 = -12 × √3

elithi Landelayo √128 ukubala ingxenye ukuthi ingase ikhishwe ngaphansi impande. 128 = 64 × 2, lapho √64 = 8. Uma ungacabanga ukuthi kuyoba lula le nkulumo ngokuthi: √128 = √ (8 ^ 2 × 2)

Thina ubhale yonke inkulumo lula imigomo:

√2 + 12 × √3-12 × √3 + 8 × √2

Manje thina tente inombolo ezizivelelayo efanayo. Awukwazi ukwengeza noma susa ukubonakaliswa ezizivelelayo ezahlukene. impande Ukwengezwa kudinga ukuhambisana nalo mthetho.

Sithola impendulo ezilandelayo:

√2 + 12√3-12√3 + 8√2 = 9√2

√2 = 1 × √2 - Ngethemba ukuthi Aljibhra isinqumo futhi bekungamelwe niziyeke izici eziningana ezinjengolwazi ngeke izindaba kuwe.

Izinkulumo kungenziwa emelelwa hhayi kuphela impande square, kodwa ziphathiswe impande cubic noma n-hydrochloric ngokwezinga.

Kuhlanganisa nekususa izimpande nge exponents ezahlukene, kodwa radicand okulingana, imi kanje:

Uma sinalo isisho efana √a + ∛b + ∜b, singakwazi lula le nkulumo ngale ndlela:

∛b + ∜b = 12 × √b4 + 12 × √b3

12√b4 + 12 × √b3 = 12 × √b4 + B3

Asiphathanga amalungu amabili enjalo ebonisa ezivamile impande. Lapha siye sasebenzisa izimpande komhiaba, esifundeka kanje: uma isibalo degrees yokukhuluma ezinkulu futhi isibalo impande Inkomba siphindwe ngesibalo esifanayo, ukubala yayo uhlala ingashintshiwe.

Qaphela: exponents ukwengeza lapho sanda.

Cabangela lesi sibonelo lapho abakhona ngokoMthetho ingxenyenamba.

5√8-4 × √ (1/4) + √72-4 × √2

Thina lizobe esethatha isinqumo mayelana zinyathelo:

5√8 = 5 * 2√2 - senza empandeni we ibuyiseke.

- 4√ (1/4) = - 4 √1 / (√4) = - 4 * 1/2 = - 2

Uma impande umzimba omelelwa ingxenyenamba, lo ingxenyenamba ayiyona ingxenye yale nguqulo, uma impande skwele dividend kanye isihlukanisi. Ngenxa yalokho, siye wathola ukulingana kuchaziwe ngenhla.

√72-4√2 = √ (2 × 36) - 4√2 = 2√2

10√2 + 2√2-2 = 12√2-2

Ngakho ukuze uthole impendulo.

Into esemqoka ukukhumbula ukuthi izinombolo engemihle ayikwazi ukhiphe impande nge ngisho okungekho. Uma ngisho radicand degree alivumi ke le nkulumo unsolvable.

Ukwengezwa izimpande engavumelekile itholakala kuphela uma ukuqondana wokuboniswa kuleli ezizivelelayo ngoba kukhona imigomo efanayo. Kuyefana nasendleleni umehluko.

Ukwengezwa izimpande ezinombolo nge exponents ezihlukene ezenziwa ngokuletha ngokwezinga ingqikithi impande kokubili imigomo. Lo mthetho nomphumela ofanayo njengoba ukuncipha zifana uma ungeza noma nekususa izingxenyana zaso.

Uma radicand linenani ophakanyiswe emandleni le nkulumo kungenziwa lula nge uzitshela ukuthi impande phakathi Inkomba kanye nezinga kukhona zifana.