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Indlela yokuthola phezulu parabola ulakhe

Esifundweni sezibalo, kukhona yonke uchungechunge ubunikazi, phakathi okuyinto ebalulekile elalihlala equation Quadratic. ukulingana okunjalo zingalungiswa kokubili ngokwehlukana futhi charting phezu Ukudidiyela izimbazo. Izimpande square zibalo kukhona amaphuzu empambana a parabola futhi iqonde oh.

umbono jikelele

I kwesibalo quadratic alinalo isakhiwo elandelayo:

ngembazo 2 + Bx + c = 0

Ekhuluma ewukuhlakanipha okwenziwe "X sika" ziphathwa njengoba eziguquguqukayo ehlukile, futhi wonke inkulumo. Ngokwesibonelo:

2x 2 + 5x-4 = 0;

(X + 7) 2 +3 (x + 7) + 2 = 0.

Esimweni lapho x imele ngokuthi buyindlela uNkulunkulu abonisa, kubalulekile ukunikela ngayo kwenombolo futhi uthole izimpande of the equation. Ngemva kwalokho, ngabo ukuba athi lo polynomial nokuxazulula for x.

Ngakho, uma (x + 7) = a, ezothando kuthatha ifomu 2 + 3a + 2 = 0.

A = 2 -4 * 3 1 * 2 = 1 ;

futhi 1 = (- 3-1) / 2 * 1 = -2;

2 = (- + 1 3) / 2 * 1 = -1 .

Lapho izimpande alinganayo -1 futhi -2, sithola lokhu okulandelayo:

x + 7 = 2 futhi x + 7 = -1;

x = -9 futhi x = -8.

Izimpande abakuzuzile x-izixhumanisi iphuzu empambana ne abscissa we parabola. Eqinisweni, ukubaluleka kwabo akubalulekile kangako uma lowo mgomo kuphela ukuthola phezulu parabola. Kodwa itulo izimpande zidlala indima ebalulekile.

Indlela yokuthola phezulu parabola

Ake ubuyele emuva kwesibalo yasekuqaleni. Ukuze siphendule umbuzo kanjani ukuthola phezulu parabola, kubalulekile ukwazi le ndlela elandelayo:

x sn = -B / 2a,

lapho x sn - value x-Ukudidiyela iphuzu oyifunayo.

Kodwa kanjani ukuthola phezulu parabola ngaphandle value-y Ukudidiyela? Thina bamelele ukubaluleka etholwe kwesibalo x futhi uthole variable oyifunayo. Ngokwesibonelo, thina ukuxazulula kwesibalo elandelayo:

x 2 + 3 = 5 0

Sesithola ukubaluleka x-izixhumanisi ngoba vertex we parabola:

x sn = -B / 2a = -3 / 2 * 1;

x sn = -1,5.

Thola ukubaluleka y izixhumanisi ngoba vertex we parabola:

y = 2x 2 + 4x 3 = (- 1,5) 2 +3 * (- 1,5) -5;

y = -7,25.

Umphumela uba ukuthi eliphakeme parabola sise izixhumanisi (-1,5; -7.25).

Ukwakhiwa parabola

A parabola kuyinto elibona nxazonke amaphuzu kokuba mpo -eksisi wesimethri. Ngenxa yalesi sizathu, isakhiwo sayo kakhulu akunzima. I nzima kakhulu - ukwenza izibalo efanele izixhumanisi amaphuzu.

Kufanele uyinaka le okuza of the equation Quadratic.

Coefficient kuthinta isiqondiso parabola. Esimeni lapho inenani negative, amagatsha baqondiswa phansi, futhi uphawu omuhle - phezulu.

Coefficient b kubonisa ukuthi wonke kuyinto parabola isandla. I emikhulu ukubaluleka, aba maningi kuyoba.

Coefficient libonisa ukufuduka kwabantu isihlobo y-eksisi ukuba umsuka parabola.

Indlela yokuthola phezulu parabola, sesivele sifundzile, futhi ukuthola izimpande, kufanele aqondiswe amafomula ezilandelayo:

D = b 2 -4ac,

lapho D - iyona discriminant, okuyilona elidingekayo ukuze umuntu lokuthola izimpande equation.

x 1 = (- b + V - D) / 2a

x 2 = (- BV - D) / 2a

Amanani etholwe x kumelwe ilingane zero abakuzuzile y, njengoba Ziyakwazi amaphuzu ezimpambanweni zomgwaqo u-x-axis.

Ngemva kwalokho siphawula ku indiza Ukudidiyela vertex we parabola kanye namagugu etholwe. Ukuze uthole isheduli ezinemininingwane eminingi kubalulekile ukuthola amaphuzu ambalwa engeziwe. Kuze kube yimanje sikhetha iyiphi x value, kwesizinda kuvunyelwe, futhi liguqule kuyo umsebenzi wesibalo. Waba yini umphumela wesibindi izibalo iyona bazihlela of iphuzu kwi-y-eksisi.

Ukuze lula inqubo ekwakheni uhlelo, ungakwazi udwebe umugqa mpo ngokusebenzisa vertex we parabola futhi perpendicular x-axis. Lokhu kuyoba eksisi wesimethri, ngayo nefunda ngayo, ukuba iphuzu elilodwa, ingachazwa kanye equidistant yesibili kusukela umugqa uyalingana.

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