Lo engaba umbuthano

Okokuqala nje, ake siqale siyichaze engaba. Lihunyushwe kwelesiHeberu elithi engaba Latin - ". Ray spokes kwamasondo" lokhu Lo engaba umbuthano - ingxenye umugqa ohlanganisa iphuzu maphakathi mbuthano, esemgwaqweni kuso. Ubude kulesi sigaba - iyona engaba. Ngo izibalo selisho lesi silinganiso usebenzisa i-Latin incwadi R.

Amathiphu okuthola engaba:

1. I ububanzi we umbuthano line ingxenye edabula isikhungo salo nokuxhuma amaphuzu ku selilonke zazo ibanga esiphezulu kusuka komunye nomunye. Irediyasi kwendilinga ilingana uhhafu ubukhulu bayo, ngakho-ke, uma wazi ububanzi we umbuthano ke ukuthola engaba yayo Kufanele sisebenzise lokhu ifomula: R = D / 2 lapho D - ubukhulu.
2. Ubude ijika avaliwe, kwakheka okuyinto ngendiza - lokhu selilonke. Uma wazi ubude bayo, lokuthola lo engaba umbuthano singasetshenziswa enemisebenzi ifomula uhlobo: R = L / (2 * π), lapho L kuyinto obuphelele circumferential, futhi π - njalo ulingana 3.14. π njalo imele isilinganiso selilonke ukuze ubukhulu bayo, ubude, zonke circumferences okufanayo.
3. Umbuthano limelela ukuma weJiyomethri oyingxenye indiza kuchazwe ijika - umbuthano. Kuleso simo, uma wazi endaweni embuthanweni, engaba umbuthano kungatholakala ngokufunda ifomula R ekhethekile = √ (S / π), lapho S indawo indilinga.
4. Irediyasi kwendilinga elalibhalwe (yisikwele) itholakala kanje: r = a / 2, lapho luluhlangothi kwesikwele.
5. Irediyasi kwendilinga circumscribed (round isikwele) ibalwa ifomula: R = √ (A2 + b 2) / 2, lapho futhi b kukhona izinhlangothi isikwele.
6. Kuleso simo, uma ungazi ubude mbuthano, kodwa wena ube wazi ukuphakama futhi ubude iyiphi ingxenye yawo, ukuthi uhlobo ifomula kungaba:

R = (4 * h2 + L2) / 8 * h, lapho h kuyinto ukuphakama ingxenye, kanye no-L Ubude balo.

Thola engaba umbuthano alotshiwe unxantathu (unxande). Esikhathini unxantathu, kungakhathaliseki ukuthi hlobo ayenakho, kungashiwo elalibhalwe kumbuthano owodwa kuphela oyedwa olungelo lakhe nendawo ngesikhathi esifanayo iphuzu lapho aphambana le bisector of emagumbini alo. unxantathu Angled anezakhi eziningi kumele kunakwe lapho kubalwa engaba umbuthano olotshiwe. Inkinga ingashiwo idatha ahlukahlukene, ngakho-ke, kuyadingeka ukwenza izibalo esidingekayo ukuze siyixazulule.

Amathiphu okuthola engaba umbuthano olotshiwe:

1. Okokuqala udinga ukwakha unxantathu nalabo Ubukhulu eziye usuvele uchaziwe umsebenzi wakho. Lokhu kumele kwenziwe ngokwazi usayizi zonke izinhlangothi ezintathu noma izinhlangothi ezimbili kanye igebe eliphakathi kwabo. Njengoba ubukhulu engela usuwazi, isimo kufanele kube umlenze ezimbili. Imilenze, okuyizinto emakhoneni okuphambene, kufanele eyabizwa ngokuthi i-futhi b, futhi hypotenuse - kokubili. Ngokuphathelene engaba umbuthano olotshiwe, it is eyabizwa ngokuthi r.
2. Ukuze ukwazi ukufaka isicelo ifomula ejwayelekile sokunquma engaba umbuthano elalibhalwe liyadingeka ukuthola zonke izinhlangothi ezintathu unxantathu kwesokudla. Ukwazi izilinganiso zonke izinhlangothi, ungathola nengxenye-azungezwe unxantathu kusukela ifomula: p = (a + b + c) / 2.
3. Uma wazi umuntu engela nasemlenzeni, kufanele sithole eduze noma oluphikisana ke. Uma kuwukuthi eduze, i-hypotenuse ingabalwa ngokusebenzisa theorem cosine: c = a / cosCBA. Uma kuwukuthi okuphambene, khona-ke ufuna ukusebenzisa ifayela echaza ifomu Sines: c = a / sinCAB.
4. Uma une nengxenye-ipherimitha, ungakwazi ukunquma engaba umbuthano olotshiwe. Uhlobo formula for engaba ngeke ngaleyo ndlela: r = √ (PB) (pa) (pc) / p.
5. Kumele kuqashelwe ukuthi le engaba kungatholakala ngokufunda ifomula: r = S / p. Ngakho, uma ukwazi umlenze ezimbili, inqubo yokubala kuyoba lula. Hypotenuse adingekayo isigamu-ipherimitha zingatholakala ku isamba sezikwele ezinye izinhlangothi ezimbili. Bala ndawo, unga, ngokuvele azalane zonke imilenze zihlukaniswe amabili futhi nenombolo ukuthi oyitholile.